Re: Electron-orbits, light-wavelength and amplitude

In article <1149469324.386468.263440@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>, "Radium" <glucegen1@xxxxxxxxxx> writes:

mmeron@xxxxxxxxxxxxxxxxxx wrote:
In article <1149462944.060524.250720@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>, "Radium" <glucegen1@xxxxxxxxxx> writes:
Hi:

Atoms contain electrons. These electrons are in specific orbits. When
an electron move from a higher energy orbit of the atom to a lower
energy orbit of the atom.

http://science.howstuffworks.com/light4.htm quote:

"The photon has a frequency, or color, that exactly matches the
distance the electron falls. "

Does this mean that a fall of greater distance produces a shorter
wavelength? Or will a greater distance fall produce a longer
wavelength? I am confused on this.

The term "distance" in the above is confusing, as it is not distance
in space but rather in "energy space". Think of it as "energy
difference", not distance.

With this in mind, yes, greater energy difference produces higher
frequency, thus *shorter* wavelength.

Also what, at the atomic level determines the amount of photons per
second released [amplitude] when the electron falls from the higher
energy level to the lower energy level?

An atom emits a *single* photon. What determines the total number of
photons, is the number of atosm emitting.

So more atoms are needed to produce a light of more intensity?

Either more atoms, or you have to force same atoms emit more
frequently.

Mati Meron | "When you argue with a fool,
meron@xxxxxxxxxxxxxxxxx | chances are he is doing just the same"
.

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