Re: Terminal Velocity of Impacting our Moon
- From: "Brad Guth" <ieisbradguth@xxxxxxxxx>
- Date: 7 Jun 2006 17:41:56 -0700
tadchem (aka Tom Davidson),
I thought that had reasonably started off this phase of topic with the
notion or premise of simply releasing a 10 kg javelin probe away from
LL-1, at roughly or exactly 1 m/s, as being intentionally directed not
into accomplishing a lunar orbit but as thrown directly at the nearest
available center of the moon below. And you're saying that's way too
complicated to have understood.
The actual location of LL-1 is certainly worth knowing, but not hardly
worth arguing about unless you're trying to avoid the primary issue of
final impact velocity as based upon whatever's given and/or selected as
the LL-1 distance from the moon that you'd like to utilize. You pick
whatever's the distance and go from there.
As far as I can tell, there's absolutely nowhere except for that probe
heading directly for the moon, that's always aligned to the very same
exact spot or perhaps that of the most significant mascon below, as for
that free-falling javelin probe to go anywhere except directly towards
that very same if not at least the approximate center of the side of
the moon that's continually facing Earth, and thereby always
unavoidably going to be the same as facing LL-1, +/- perhaps within 0.1
degree. Thus there is no such 2.4 km/s involved unless you've intend
to force a given probe into a fully orbital dive. As for the otherwise
wussy 4.6264 m/s worth of surface rotation isn't hardly worth taking
into orbital account, especially since it remains essentially
synchronised with the orbital velocity of LL-1 that's offering 163.15
m/s of it's orbital velocity.
Please do feel free to explain if the above orbitals of LL-1 at 163 m/s
and of the lunar deck at 4.63 m/s are otherwise, as I believe it's a
relatively important and a very basic factor in dealing with our
physically dark and nasty moon, at least from the rather nifty
perspective of LL-1.
I appreciate your V(f), whereas "I get 1631.4 m/sec", which seems a wee
bit if not a whole lot too good to be true, meaning way too slight of a
final velocity to be true. So, for the moment I'll ponder that number
and do a little dyslexic rethinking on my own. Just don't expect my
next move to make any better sense than what I'd started off with.
"As it is all gibberish, your statement proves nothing." Not that I
was trying to prove anything, other than for coming up with the
free-fall V(f) of impacting our moon from the starting point of LL-1
and having that starting velocity of 1 m/s. Obviously you still
haven't a freaking clue, not even a SWAG worth of being even remotely
close to the target impact velocity.
Perhaps you'd merely forgoten that this distance from LL-1 to the lunar
deck of 161,290 -1,738 = 159,552 is in km, not meters, and certainly
I'd have to perceive as for much less being the case if "That would be
the velocity of a javelin 'dropped' from interplanetary space somewhere
near the earth's orbit onto the moon", which makes absolutely no final
velocity sense within the context of this topic/argument whatsoever.
Perhaps "you are committing a logical fallacy here - your conclusion
does not follow from the premises" of my original topic configuration,
that which apparently is simply too Klingon encrypted to understand.
Sorry about that.
-
Brad Guth
.
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- Re: Terminal Velocity of Impacting our Moon
- From: tadchem
- Re: Terminal Velocity of Impacting our Moon
- From: Brad Guth
- Re: Terminal Velocity of Impacting our Moon
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- Re: Terminal Velocity of Impacting our Moon
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