Re: GRAVITATION


and the acceleration equation.

Now, if you resolve G in that equation, you get

F = (4 pi^2 r^3)/(M T^2) * Mm/r^2

symplifying, you get

F = m (4 pi^2 r)/T^2

Now, to square the radius you need to multiply
and divide by mutually reducible occurrences of
the radius

F = m (4 pi^2 r^2)/r T^2

But since (2 pi r) is the length of the orbit,
then (2 pi r)/T is the velocity

So, you can resolve for the velocity

F = m v^2/r = 8.238721759E-8 N

or

F = ma = 8.238721759E-8 N

This is why you cannot intermix the Coulomb equation
with the gravitational equation. They simply are
two different representation of the very same
classical acceleration equation F=ma expressed
differently. You can substitute one for the other,
but you cannot intermix them.

For the hydrogen atom,

F = ke^2/r^2 = GMm/r^2 = ma = 8.238721759E-8 N

André Michaud
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did you assume that the electron is orbiting around the nuc .????

ATB
Y.Porat
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