Re: Are physics cranks employed?




"cnctut" <cnctutwiler@xxxxxxxxxxxxx> wrote in message
news:1156089480.802480.52800@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
|
| Sorcerer wrote:
|
| --some snipped and (numbers) added for clarity--
|
| >(1) x' = x-vt
| >(2) xi = x'/sqrt(1-v^2/c^2)
| >(3) xi-x' = xi[1- 1/sqrt(1-v^2/c^2)]
| >(4) x'-xi = -xi[1- 1/sqrt(1-v^2/c^2)]
|
| > Androcles
| //
|
| Tut writes:
|
| Everyone makes simple math mistakes--how many Mars probes are in pieces
| on its surface?
|
| Let's try this:
|
| Given your equations (2) & (3):
|
| Let P = sqrt (1-v^2/c^2) then from equation (2) by substitution
|
| (2) xi = x'/P then x' = xiP
|
| Solving for xi - x' by substituting x' = xiP, then
|
| (5) xi -x' = xi - xiP then
|
| (6) xi - x' = xi ( 1 - P) but P = sqrt(1-v^2/c^2) and substituting
| back into (6)
|
| (7) xi - x = xi ( 1 - sqrt(1-v^2/c^2) which is not what is shown in
| equation (3)
|
| Hope this helps!
|
| Best Wishes,
|
| Tut


Let's try this:

You've missed the prime of x.
Substituting square brackets for parentheses because your parentheses in

(7) xi - x = xi ( 1 - sqrt(1-v^2/c^2)
^^^ ^^^ ^^^ ^^^

x' LEFT LEFT RIGHT

are not paired, we have

(7a) xi-x' = xi[1- sqrt(1-v^2/c^2)]
^ ^ ^ ^^

Check:
(3) xi-x' = xi[1- 1/sqrt(1-v^2/c^2)]

xi-x' = xi- xi/sqrt(1-v^2/c^2)
-x' = -xi/sqrt(1-v^2/c^2)
x' = xi/sqrt(1-v^2/c^2)
x'*sqrt(1-v^2/c^2) = xi.

so
xi = x' * sqrt(1-v^2/c^2) <> x'/sqrt(1-v^2/c^2)

hence (3) is indeed apparently incorrect, BUT...

you've stopped my fun with Rabid Dork, who was unable to show
that (3) was incorrect (Please don't tell) because Rabid Dork thinks
xi = x',
Reference:
http://groups.google.com/group/sci.physics.relativity/msg/fde91ced0fbfef81

quote:
Exercise [2]: can you explain in the context of following equations:
x = c t
x' = c t' ,
what is the physical meaning of the variables
x: ?
t: ?
x': ?
t': ?
c: ?
/end quote
(no mention of tau or xi) which in reality it does,
because the c in sqrt(1-v^2/c^2) is 0/0
(ref
http://www.androcles01.pwp.blueyonder.co.uk/DominoEffect.GIF )

and (3) is just as correct the way it was because sqrt(1 - v^2/ [0/0]^2) =
1.


Everyone makes simple math mistakes--how many relativists are shitheads?
There is Einstein, Phuckwit Duck, Blind Poe, Rabid Dork Van de merde,
and I'm not quite sure whether Toot is a relativist, but missing primes
and parentheses is naughty.

"HE was and would continue to be a teacher, and as with most skilled
teachers,
he would occasionally tell lies as harsh exemplars of a deeper truth." ---
Tom Clancy, "Executive Orders"

Androcles.



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