Re: Are physics cranks employed?


Sorcerer wrote:
"cnctut" <cnctutwiler@xxxxxxxxxxxxx> wrote in message
news:1156096655.990934.10130@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
|
| Sorcerer wrote:
| > "cnctut" <cnctutwiler@xxxxxxxxxxxxx> wrote in message
| > news:1156089480.802480.52800@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
| > |
| > | Sorcerer wrote:
| > |
| > | --some snipped and (numbers) added for clarity--
| > |
| > | >(1) x' = x-vt
| > | >(2) xi = x'/sqrt(1-v^2/c^2)
| > | >(3) xi-x' = xi[1- 1/sqrt(1-v^2/c^2)]
| > | >(4) x'-xi = -xi[1- 1/sqrt(1-v^2/c^2)]
| > |
| > | > Androcles
| > | //
| > |
| > | Tut writes:
| > |
| > | Everyone makes simple math mistakes--how many Mars probes are in
pieces
| > | on its surface?
| > |
| > | Let's try this:
| > |
| > | Given your equations (2) & (3):
| > |
| > | Let P = sqrt (1-v^2/c^2) then from equation (2) by substitution
| > |
| > | (2) xi = x'/P then x' = xiP
| > |
| > | Solving for xi - x' by substituting x' = xiP, then
| > |
| > | (5) xi -x' = xi - xiP then
| > |
| > | (6) xi - x' = xi ( 1 - P) but P = sqrt(1-v^2/c^2) and substituting
| > | back into (6)
| > |
| > | (7) xi - x = xi ( 1 - sqrt(1-v^2/c^2) which is not what is shown in
| > | equation (3)
| > |
| > | Hope this helps!
| > |
| > | Best Wishes,
| > |
| > | Tut
| >
| >
| > Let's try this:
| >
| > You've missed the prime of x.
| > Substituting square brackets for parentheses because your parentheses in
| >
| > (7) xi - x = xi ( 1 - sqrt(1-v^2/c^2)
| > ^^^ ^^^ ^^^ ^^^
| >
| > x' LEFT LEFT RIGHT
| >
| > are not paired, we have
| >
| > (7a) xi-x' = xi[1- sqrt(1-v^2/c^2)]
| > ^ ^ ^ ^^
| >
| > Check:
| > (3) xi-x' = xi[1- 1/sqrt(1-v^2/c^2)]
| >
| > xi-x' = xi- xi/sqrt(1-v^2/c^2)
| > -x' = -xi/sqrt(1-v^2/c^2)
| > x' = xi/sqrt(1-v^2/c^2)
| > x'*sqrt(1-v^2/c^2) = xi.
| >
| > so
| > xi = x' * sqrt(1-v^2/c^2) <> x'/sqrt(1-v^2/c^2)
| >
| > hence (3) is indeed apparently incorrect, BUT...
| >
| > you've stopped my fun with Rabid Dork, who was unable to show
| > that (3) was incorrect (Please don't tell) because Rabid Dork thinks
| > xi = x',
| > Reference:
| >
http://groups.google.com/group/sci.physics.relativity/msg/fde91ced0fbfef81
| >
| > quote:
| > Exercise [2]: can you explain in the context of following equations:
| > x = c t
| > x' = c t' ,
| > what is the physical meaning of the variables
| > x: ?
| > t: ?
| > x': ?
| > t': ?
| > c: ?
| > /end quote
| > (no mention of tau or xi) which in reality it does,
| > because the c in sqrt(1-v^2/c^2) is 0/0
| > (ref
| > http://www.androcles01.pwp.blueyonder.co.uk/DominoEffect.GIF )
| >
| > and (3) is just as correct the way it was because sqrt(1 - v^2/ [0/0]^2)
=
| > 1.
| >
| >
| > Everyone makes simple math mistakes--how many relativists are shitheads?
| > There is Einstein, Phuckwit Duck, Blind Poe, Rabid Dork Van de merde,
| > and I'm not quite sure whether Toot is a relativist, but missing primes
| > and parentheses is naughty.
| >
| > "HE was and would continue to be a teacher, and as with most skilled
| > teachers,
| > he would occasionally tell lies as harsh exemplars of a deeper
truth." ---
| > Tom Clancy, "Executive Orders"
| >
| > Androcles.
|
| Tut writes:
|
| I wish I could say the x vs x' was done on purpose--nope, just a simple
| typing error corrected in a follow-up post. Yup, forgot a ' ) ' too.
|
| Thanks for the correction.
|
| Tut
Ok, no problem. Now be a good chap and correct a velocity that reverses.
After all, anyone can make a mistake, including Einstein.
It's only a problem if the mistake is not corrected, right?
Here it is:
http://www.androcles01.pwp.blueyonder.co.uk/DominoEffect.GIF

Or was it a deliberate mistake so that Einstein could perpetrate a hoax?
In agreement with experience we further assume Einstein was a huckster.
Do WE not?
Androcles

Androcles,

I don't know anything about the velocity reversing your talking about,
or what you're trying to show with the moving graph--just that it
appears to me that your f ' (x) is messed up. Has anyone suggested this
from a mathematics perspective? Could you explain without my need to
read the 1905/06 paper(s).

Thanks,

Tut

.

Quantcast