Re: Are physics cranks employed?

In sci.physics, cnctut
<cnctutwiler@xxxxxxxxxxxxx>
wrote
on 20 Aug 2006 18:17:54 -0700
<1156123074.900193.209240@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:
Androcles:

I did scan two translations of his papers--and did find something
similiar to your equation 2AB/(t'A-tA). Perhaps the translation
equation and yours are the same--there appeared to be some difference
though.

Androcles is on record (I'd have to find it) that the
equation should actually be

(AB+BA)/(t'A-tA)

which in his mind evalutes to 0/0. The errors in such
logic are considerable but there is a minor translation
issue with the term "Lichtgeschwindigkeit", which can
either be translated "lightspeed" or "velocity of light".
Most people take the former in which case the expression
reduces to

(|AB|+|BA|)/(t'A-tA)

or

(2|AB|)/(t'A-tA)

I'm not sure how "self-evident" this is, in Einstein's
paper, but it's a logical method by which to measure the
average speed of a round trip, assuming the destination
B is known, space is isotropic, and the person making the
time measurement can't move.

It's probably worth noting that, if one assumes a
frictionless aether theory (or BaT/BaTh, which has the same
equations if one doesn't assume velocity decay) and A and
B are motionless, that the equation (|AB|+|BA|)/(t'A-tA) =
2d/c, as it should be. However, if one takes an absolute
aether theory with the velocity of AB with respect to that
aether being v, then one gets

t_R = d/(c+v) + d/(c-v) = 2cd/(c^2-v^2) > 2/c.

If one extends to three dimensions and the velocity of AB
is resolved into components (v,w), then one gets

t_R = d/sqrt((c+v)^2+w^2) + d/sqrt((c-v)^2+w^2) > 2/c

as well -- the crabwind problem.

(Addition of another dimension is pointless since one can
simply rotate the plane containing AB until the velocity of
AB with respect to the aether is parallel thereto/contained
therein.)



I didn't see the f ' (x) equation that you show on the website you
gave--but it may be in the 1905 papers also. To me, the f ' (x)
equation on your website doesn't seem to fit what I would expect a
derivative of f(x) to be by general definition.

Best Wishes,

Tut


http://www.fourmilab.ch/etexts/einstein/specrel/www/

does not appear to have f'(x) anywhere -- or even f(x). phi(v), yes,
but not f(x).

--
#191, ewill3@xxxxxxxxxxxxx
Windows Vista. Because it's time to refresh your hardware. Trust us.
.

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