Re: decelerating electrons emitting photons

On 17 fév, 20:16, jjsav...@xxxxxxxxx wrote:
Hi everyone,
Suppose you have two electrons, electron A and electron B. The
both start at initial velocity V_i at time T_0 and decelerate to final
velocity V_f. However, electron A decelerates in a short time T_a,
while electron B decelerates in a longer time T_b, so T_a < T_b. Does
this mean that electron A emits a few high-energy photons (like x-
rays), while electron B will emit many low-energy photons (infrared),

Possibly.

but the sum of the energies of each electron's photons will be the
same?

Definitely.

Each electron has the same initial kinetic energy and the same
final energy, so the energy lost by each will be the same. But, why
doesn't electron A emit lots and lots of infrared photons, or why
doesn't electron B emit one or two x-rays?

If deceleration is not instanteneous, it seems that photons have
to be emitted in relation with the deceleration rate. How could it be
otherwise?

If the energies are the same, how does the rate of deceleration affect
the energy of each photon emitted?

The _total_ energy is the same, from your premises. this is what
is certain.

The energy freed as photons cannot exceed the energy that becomes
in excess at any given moment, no ?

For example, if you "zoom in" on electron A's
deceleration and pick two intermediate times T_a1 and T_a2 (between
T_0 and time T_a), the energy lost by electron A in this time slice
will be equal to the energy of an infrared photon, so why doesn't it
emit an infrared photon?

It possibly does. Who knows. From theory, it must.

In reality, this is like asking if the lead dust that remains after
you sharpen a lead pencil would have been able to trace the
word "lead". Well, it could possibly have.

Look up bremmstrahlung and synchrotron radiation.

Your guess is as good as anyone elses on such fine
hair splitting.

Thanks,
John

André Michaud

.

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