Re: physics help

On Feb 28, 4:31 pm, fest_...@xxxxxxxxx wrote:
for the non-physics minded person?

ive done the problem, i just dont know what certain things stand for,
and i dont quite understaND WHY THE ANSWER WAS WRITTEN THE WAY IT
WAS. im sorry i DID NOT mean to yell. caps lock got hit.

problem and my method appears here.

http://www.topix.net/forum/science/physics/TMCNC9KHL8NL2V8HR

If you call upwards the positive direction, then acceleration
of gravity is downwards, and so negative.

If you call upwards the "x" direction, then the equation of
up-and-down motion is

x = x0 + V0 t + 1/2 a t^2

x0 is the position at t = 0, that is the position at time zero.
In the problem it is zero.

V0 is the speed at t=0. In the problem it is +128 ft/s, positive
meaning upwards.

x is the position at time t.

All clear now?
Socks

.