Re: Question about Kepler's second law

On Apr 14, 5:46 pm, Phineas T Puddleduck <phineaspuddled...@xxxxxxxxx>
wrote:
In article <phineaspuddleduck-8DE2E9.22425614042...@xxxxxxxxxxxxxxxxx>,
Phineas T Puddleduck <phineaspuddled...@xxxxxxxxx> wrote:





In article <1176586599.745388.92...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"Peter" <Poakfi...@xxxxxxx> wrote:

Note that momentum is considered to be a vector. Since
the velocity changes direction around the track, mrw
treated as a vector expression ( m*(r x w) ) will not be
a constant over the whole track.

Yes, momentum is a vector. mrw is a vector, because r is a vector; w
is not a vector, it is an angular displacement, which is not a vector,
over time.

Peter

Nope

Angular velocity is a vector too, hence the cross product

(Point of contention - -actually a pseudovector, but it still uses the
cross product)

- Show quoted text -

The cross product is also a pseudovector.

Peter


.

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