Re: WHERE THE GRAVITATIONAL REDSHIFT FACTOR COMES FROM



On 9 May 2007 16:18:07 -0700, eugene_stefanovich@xxxxxxx wrote:

On May 9, 3:16 pm, John C. Polasek <jpola...@xxxxxxxxxx> wrote:

Actually not. There is another test, Brault's.
The correct expression purely for the increase in c is c'/c=sqrt(1 +
2MG/Rc^2) = sqrt(1+2V/c^2) ~ 1+ V/c^2 = 1+MG/Rc^2
This is demonstrated in Brault's experiment on the Sun's D-line which
he quantified as an increase of +635 m/s in c on leaving the sun.
Using the mass and radius of the sun,
dc = c*MG/Rc^2 = 635 m/s
In the Shapiro effect there is space dilation also that gives the
doubling effect and there it would be 1+ 2V/c^2.
Brault's experiment is in MTL Gravitation.
John Polasek


Unfortunately, I don't have MTL Gravitation, but I have two dozen of
articles about the gravitational shift of Solar spectral lines. At
some point I was interested in this phenomenon and spent a lot of time
reading about it. I suspect you misunderstood the speed of 635 m/s
which is often quoted in connection with the Sun redshift. In my
understanding, this is the (imaginary) speed which produces a Doppler
shift numerically identical to the gravitational redshift observed on
the Sun's surface. Nobody is saying that this is the actual speed of
atoms on the Sun's surface. Moreover, this is not the amount by which
the speed of light changes. This is just a convenient (though rather
abstract) measure of the effect of Sun's gravity on spectral line
frequencies.

Eugene.

No, I didn't use anything from MTL, except to cite Brault's
experiment.

I derived it from own theory of gravity which you can see on my
website http://www.dualspace.net, the gravity paper. I added 2 terms
to Newton's equation to explain the actual cause of gravity.

Eq. 3 says
cdc/dr = MG/r^2
which when integrated from Rsun to oo gives
Dc = +Mg/Rc =+635m/s Sun, or 0.208m/s for Earth.
Eq. 3 says that c is reduced in gravity and the equation tells what
velocity it gains on the way out. Furthermore, the frequency in the
well becomes low and retains the same depressed value, but the
wavelength in the well remains the same since L = c/f (both reduced).
The net result is the wavelength stretches on the way out and keeps
its reduced frequency.

If you integrate the other new term dc^2/2dr from R to oo on you get
c'/coo = sqrt(1-2MG/Rcoo^2)
the reduced velocity c' giving the redshift.

General relativity does it this way
dtau/dt = sqrt(-g00) = sqrt(1-2MG/Rc^2)
It's the same expression except relativity tries to squeeze time and
I'm saying it can't be done.
John Polasek
.



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