Moment of Inertia of a thin circular disc
 From: qwerty <qwerty@xxxxxxxxxxxxxxxxxxxxxxxxx>
 Date: Tue, 19 Jun 2007 22:27:08 +0000 (UTC)
The disc has uniform density. The mass of a slice (like a pizza)
of the disc is:
dm = (M/2pi) * dtheta
theta: the angle of the slice in radians
M: the mass of the disc
So to find the moment of inertia:
I = (Integral from 0 to 2pi)R^2 dm = M*R^2
That's incorrect, as the moment of inertia of a circular disc is
M*R^2/2.
So what am I doing wrong?
.
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