Re: P AND Q 2 PARTICLES
- From: Divij Rao <divij_urdbest@xxxxxxxxxxx>
- Date: Sun, 05 Aug 2007 02:21:09 -0700
On Jul 15, 11:03 pm, s...@xxxxxxxxxxxx wrote:
On 15 juil, 01:43, Divij Rao <divij_urdb...@xxxxxxxxxxx> wrote:
On Jul 10, 9:47 pm, s...@xxxxxxxxxxxx wrote:
On 8 juil, 07:50, Divij Rao <divij_urdb...@xxxxxxxxxxx> wrote:
First hunch is that you are dealing with an asymptote,
with q trailing behind p at AB - deltaAB
i dont know so much...in simpler words...plz
Hope this helps.
didnot understand the meaning .
AndréMichaud
thank you,
Divij
Sorry for the delay, I just saw your post.
I requote your question here for convenience:
A and B are 2 positions in coordinate system, particles p,q are
at A and B respectively. p moves perpendicular to AB, q is
directed towards p always, both have speed= v m/s, distance
b/w them initially is d, find the distance b/w them at time=infinity.
I will try to make you see what I conclude.
Imagine position A and B as lying on a horizontal line (x axis ?)
you have p initially located at A and q initially located at B
the distance between p and q is d, and both p and q have the
same velocity, so imagine p and q tied together by a string,
which will force q to always move towards p as p moves away.
now if you set the particles in motion at velocity v, p is going
to move upwards vertically with q being pulled along, always
moving towards p.
Now, the string is mentioned only so that you can clearly
see how q can always point towards p.
At the beginning, q will move almost horizontally but will
progressively angle upwards since it is following p which
is moving vertically upwards.
After some time, q will end up moving vertically as it
trails behind p. since both have the same velocity,
q will be unable to catch up with p and will forever
follow behind.
You are dealing with uniform motion for both p and q
I did not do the actual math, so I don't know whether
q will catch up some with p. I expect so, but I really
wouldn't know without doing the actual math.
AndréMichaud
excellent idea!
but i m still not sure... suppose p has moved a distance x,
after some time say t, by speed, we cant say that distance
between p and q is the same, as per the xample, the string
MAY become loose.
That was my point, precisely. You must do the calculation
to ascertain the final distance between p and q.
maybe u r correct.
What is uncertain in my mind, without doing the actual
calculation, is whether or not on the first leg of the motion
p will come any closer to p, but I am positive that once
q tends towards moving vertically (following p since it is always
pointing towards p) the distance will tend to become stable,
and remain stable, since both have the same velocity.
André Michaud
thanks a lot, all comments will be appreciated.
Regards,
Divij- Hide quoted text -
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yes, the distabnce bet them becomes constant after time infinity, but
how to calculate that?
can resolving the speeds of q along p be useful?
if so how?
.
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