lorenz transformation

Hello,
Can somebody clarify this for me?
if two spacecrafts approach at the speed of v=0.8c and w=0.8c, the
lorenz transformation gives their relative approach speed by u= (v+w)/
(1+vw/c²) = about 0.975c. ok fine, I understand it can not be more
than 1c.
Now let's suppose that they run on opposite directions at those same
speeds, is this relation still valid? If I use the same relation, I
would state v=0.8 and w= -0.8c, but then the result is u=0 ???. How
should it be calculated?

.

Relevant Pages

  • Re: lorenz transformation
    ... if two spacecrafts approach at the speed of v=0.8c and w=0.8c, ... lorenz transformation gives their relative approach speed by u= / ... speeds, ... Go back to the first situation. ...
    (sci.physics)
  • Re: lorenz transformation
    ... if two spacecrafts approach at the speed of v=0.8c and w=0.8c, ... lorenz transformation gives their relative approach speed by u= / ... Now let's suppose that they run on opposite directions at those same ... speeds, ...
    (sci.physics)
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