Re: lorenz transformation and spped of light
- From: "JM Albuquerque" <jmDOTa2@xxxxxxx>
- Date: Thu, 20 Sep 2007 15:18:49 +0100
"Jeckyl" <noone@xxxxxxxxxxx> escreveu na mensagem
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"Chrisd5000rouge" <christian.duez@xxxxxxxxxxx> escreveu na mensagem
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Two spacecrafts running at opposite directions at 0.8c each, the
lorenz transformation says that their relative speed perception is u=
(0.8c+0.8c)/(1+(0.8c*0.8c/c²))= 0.975c.
It not a "perception" .. it IS their relative speed (ie the speed of the
second spaceship in the iFoR of the first). SR doesn't talk about optical
illusions :)
That's completely nonsense.
Of course it's a perception, since the problem starts saying:
Two spacecrafts running at opposite directions at 0.8c each.
Why cannot the reality be that of two spacecrafts running at
opposite directions at 0.8c each?
We build two spacecrafts, we place then back-to-back,
and we fire them with a program that guarantees that in
a given time and a given distance, both will be running
at 0.8c.
So we know what the reality is.
The value 0.975c is only a perception, not the reality.
Nevertheless, we can imagine that each spacecraft has a
pilote and that pilote wants to compute how much time will
it take to receive signals from the other spacecraft.
Each pilot, of each spacecraft can compute its absolute
speed relative to the distant fixed stars. Now, each pilot
wants to know where the other spacecraft is (what distance).
Both spacecrafts send light signals to each other.
Each pilot measures the redshift of those signals and
come up to the conclusion that such redshift indicates
a relative speed of 0.975c
Since each pilot knows its absolute speed from the
fixed stars to be 0.8c, it will be able to compute the
other spacecraft speed "x" to be that:
(x+0.8c)/(1+(x*0.8c/c²))= 0.975c.
So, that x = 0.8c.
Knowing its speed and the others speed, each pilot
can predict where in "reality" the other spacecraft is.
That's what SR is all about - RELATIVITY.
Not the reality.
.
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