Re: The biggest attention-getters in " Sci.Physics ".
- From: Eric Gisse <jowr.pi@xxxxxxxxx>
- Date: Tue, 8 Jan 2008 22:15:34 -0800 (PST)
On Jan 8, 3:41 am, NoEinstein <noeinst...@xxxxxxxxxxxxx> wrote:
On Jan 8, 12:34 am, Eric Gisse <jowr...@xxxxxxxxx> wrote:
On Jan 7, 7:52 pm, Sam Wormley <sworml...@xxxxxxxxx> wrote:
NoEinstein wrote:
On Jan 7, 10:24 pm, Sam Wormley <sworml...@xxxxxxxxx> wrote:
NoEinstein wrote:
Or... "squeaking wheels get the grease." Einstein doesn'tI call NoEinstein's attention one more time to this excellent online
explain how GPS works, he only lucked up with an analogy that
approximates it. I don't think Tom believes Einstein in that regard.
But if so, I will need to do some... egdy kating of him.
publication: Relativistic Effects on Satellite Clocks
http://relativity.livingreviews.org/open?pubNo=lrr-2003-1&page=node5....
Dear Sam: Your niche is GPS and clocks in space. My niche is
mechanics and optics. This is my post. To engage me in "arguments"
discuss M-M or Coriolis. Thanks! -- NoEinstein --
Mechanics, eh.... What text(s) dis you study classical
mechanics from? I'm curious to see if we studied from similar
textbooks. Thanks.
-Sam
If he can complete even one problem from an upper division
undergraduate / graduate textbook on analytic mechanics, I'd eat my
hat.- Hide quoted text -
- Show quoted text -
Dear Eric: I solve problems as needed, not as some contest to best
anyone. That reminds me: Did you ever calculate the angle of a side
of a pyramid that has the four corners on the "equator" of a
hemisphere, with the tip of the pyramid touching the north pole of the
hemisphere? Probably outside of your "courses"... -- NoEinstein --
No, because I'm not in highschool taking a geometry course where I
compute angles all the time. Not that it is especially hard.
Slice the sphere along the pyramid's base. The triangle that subtends
a circle is an equilateral triangle - 60 degrees per corner. I can't
remember how to prove this using high school geometry but I can prove
it through calculus.
Slice the sphere through the north pole. The resulting triangle has
three contact points on the sphere, with the center of the base on the
sphere's center. The three rays extending from the center are a radius
- and all equal. Remember that tan(theta) = opposite / adjacent -
tan(theta) = r/r = 1. The angles of the pyramid's sides with respect
to the base are 45 degrees.
My education is general, it teaches me to understand enough to
approach any situation.
.
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