Re: How to Replicate NoEinstein's M-M Invalidation (is Copyrighted.)

On Jan 21, 8:09 pm, Eric Gisse <jowr...@xxxxxxxxx> wrote:

Eric: Ah! You are seeing truths! In a moving apparatus, the
distances the light must travel are determined by how far the
apparatus moves WHILE the light is in transit to a mirror or the
target. But since the velocity of the light is: ('c' plus or minus
v), and the velocity of the respective mirror or target is exactly the
same, the light in M-M CAN speed up above 'c' or slow down below 'c',
yet the light will always require the same amount of TIME to circuit
the full courses!

Only if the speed of light is constant, otherwise there would be
interference from different path lengths.
This is well known and very obvious. Why have you spent a week
explaining what is already known?

Eric, I've already answered that, and at length in my previous reply
to you.

M-M proves the above, IF you will just slow down enough to do some
middle school algebra and verify this for yourself. So far, not a
single reader has been willing to even try... Guy, you at least 'tried'
to find the angle of the side of a pyramid. Why don't you try seeing
if you can replicate my invalidation of M-M (for detecting light
velocity). It would be wonderful to have someone with your energy as
an ally, rather than as an antagonist. -- NoEinstein --

Since you can't explain how my result regarding the angles in the
inscribed pyramid-in-sphere was wrong in any way, I don't think it
aids your cause to bring it up.

To solve spatial problems, one needs to have space visualization
skills! The angle of the side of a pyramid problem which I caught
you on stated: "The four corners touch the equator of a hemisphere;
and the tip of pyramid touches the north pole of the same
hemisphere." That was where you didn't read. The angle of the side
must be such that those five points TOUCH on a hemisphere.

Your most erroneous assumption was: "The angles of the three edges of
a side are 60 degrees." Apparently, you think that a pyramid can't
have but one angle of side slope! Well, if the problem had been
stated that the four sides are each equilateral triangles, then your
side angle "guesstimate" of 45 degrees would have been correct.
However! Though the four corners of your pyramid could hit the
equator of a hemisphere, the tip of such a pyramid would NOT touch the
north pole of the hemisphere.

The only side angle of a pyramid that will touch both the equator AND
the north pole is 54.7 degrees. Therefore, since you missed the
correct answer, you fail to show that you have spatial visualization
ability so necessary if you are become a physicist who can contribute
anything. Learn from your mistakes, or give it up, Eric.

I tire of you continually referencing middle school algebra like it
matters one goddamn bit.

It 'matters' only if you can, and will do it. If basic math is... below
your dignity, you are in the ranks of Lorentz and Einstein. Doing
basic math was below their dignity, too.

The analysis for a Michelson interferometer
is quite simple and I have done it, as have countless others over the
past century or so.

As with that pyramid problem, you "doing" a mathematical analysis of
anything is suspect. Your psychological problem: You are a hot-shot,
who shoots from the hip without really thinking anything through. In
some ways you are 'smart', Eric, but you have let that go to your
head. Unless and until you can realize and correct your own
fallibility, you will never be more than a flash-in-the-pan.

But because you believe the analysis proves you right, why don't you
provide the analysis yourself instead of trying to goad me or others
into doing it for you?

If I present my various mathematical disproofs, you, or the other
readers, must either check my math step by step, or do the math for
yourselves and compare your results to mine. I prefer to invite you
and others to do the latter. That is the subject of this very post.
Your claiming to have done so is a lie, because, as with the pyramid
problem you delude yourself concerning your ability to analyze
anything spatial. Loose your hot-shot attitude, Eric, or continue to
be the laughing-stock that you are. -- NoEinstein --



.

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