Re: Converting Temperature Difference to Watts
- From: Dwib <dwibdwib@xxxxxxxxx>
- Date: Wed, 6 Feb 2008 10:31:40 -0800 (PST)
On Feb 6, 11:26 am, yiminr...@xxxxxxxx wrote:
Greetings,
A chip on a board has a surface temperature of 46 C, or 25 C warmer
than ambient. The chip size in cubic mm is approximately 5 x 3 x 1.
The chip is surface mounted and glued to the board and it is radiating
some heat through that medium. The circuit is running at 3.3 V.
Are there formulae to determine heat loss in W and current consumption
in A? Do I need more inputs? With some assumptions, can I at least get
an upper and/or lower range of current consumption?
Any references, on-line or otherwise are welcome.
Regards,
YR
You could use Stefan-Boltzmann law ( http://en.wikipedia.org/wiki/Stefan-Boltzmann_law
)to determine the total radiant power for each temperature and then
subtract the two power values to get a difference in radiant power.
Dwib
.
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