Re: Sunspots

Hi again Mr. Davidson.
I double checked your and my figures and find
they are in very good agreement.

On Feb 10, 12:26 pm, tadchem <tadc...@xxxxxxxxxxx> wrote:
On Feb 10, 2:31 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:

Tell us, given a 100 meter radius iron meteor
dropped into the Sun from infinity, what will be
the TNT equivalent in energy?
Ken

R = 100 m => V = 4.2e6 m^3

Iron density = 7.87 g/cm^3 = 7.870 kg/m^3

mass = 7870 * 4.2e6 = 3.3e10 kg

G = 6.67e-11 N m^2 /kg^2

R(sun) = 6.955e8 m

M(sun) = 1.99e30 Kg

Energy = G*M*m/R = 6.3e21 J = 1.5e9 kiloton

Yes, I was somewhat conservative, see density here,
http://en.wikipedia.org/wiki/Iron

http://www.onlineconversion.com/energy.htm

Sun's power output = 3.846e26 watts = 3.846e26 J/sec

The sun's chromosphere is about 10,000 km deephttp://en.wikipedia.org/wiki/Chromosphere

Your meteor would be impacting at the sun's escape velocity, 617.5 km/
sechttp://en.wikipedia.org/wiki/Escape_velocity

and would require 16 seconds to pass through the chromosphere, during
which time it would burn up, dissipating its 6.3e21 J of kinetic
energy. In this same 16 seconds the sun would be emitting 6.15e27 J of
its own energy.

The six orders of magnitude difference means that the meteor would
increase the sun's apparent luminosity by barely 0.0001%

The "normal" variations in total solar irradiance are on the order of
1 watt/m^2 (about 0.07%) and vary in synchrony with the sunspot cycle.http://www.nature.com/nature/journal/v443/n7108/fig_tab/nature05072_F...

Unless you are actually proposing that there are on the average about
700 meteors averaging 100 meters in diameter
(radius)
striking the sun every 16 seconds for a period of years,

Agreeable enough. To produce a .01% variation in Sun's
radiance, we'll need the energy delivered by ~ 3*10^17
(metric tons) @ Sun escape velocity per year.

I figure that using,
Sun's energy output per year is ~ 1.2*10^34 J ,
and you figured ~6*10^21J / 200m meteor.

waxing and waning in an 11 year cycle,
then the data do not support your hypothesis.

Sure it does, it coresponds to ~ 30,000 tons entering
Earths atmosphere/year, which is very close to
independant estimates. #
Our calculations are right on the button.

Of course, if you ARE making such a proposal, then you will be hard
put to account for all this mass inside the solar system - this stuff
should all be orbiting the sun from within the orbit of Saturn to have
an 11-year period.

Please review my OP, the sunspot cycle depends
on the galactic structure and the spoke cross-section.

Celestial mechanics does not permit any interstellar phenomena with
such a short period due to the strength of the sun's gravity.

Explained above.

Tom Davidson
Richmond, VA

# A mass falling on the Sun has an amplified energy,
compared to Earth due to escape velocity differences.
So the amount of matter in falling in Earth is reduced
by that amount of kinetic energy difference.

Best Regards
Ken S. Tucker
.

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