Re: equations for inertial simulator
- From: Robert <renenkel@xxxxxxxxxxx>
- Date: Sat, 23 Feb 2008 14:13:08 -0800 (PST)
On Feb 23, 3:15 pm, j...@xxxxxxxxxxxxxxxxxxxx wrote:
How about a much smaller pendulum going through a series of pulleys
such that the mechanical advantage is for the pendulum, thus making,
say a 10 pound bob, feel like the 1 ton bell?
The length would of course have to be diddled to get the same period
as the bell.
Jim Pennino
The trouble with any sort of mechanical advantage system is that if
you arrange it to make the rope feel harder to pull, it also reduces
the distance the rope moves through. Since the design goal is to make
the person pulling on the rope feel like he's manipulating the heavy
bell, both the force and the distance of rope movement need to be
correct.
So it looks like the torque produced by the motor can't depend simply
on its position, since it also depends on the external torque imposed
by the person pulling on the rope. To use the same example I had
before, suppose the rope is held still at such a position as to hold
the shaft 90 degrees up from equilibrium. Then the motor must provide
a large torque to simulate the weight of the heavy bell. However, if
the rope is then suddenly released, the motor must provide a much
smaller torque in the same position, only enough to accelerate the
motor itself in the same way as the large bell would if let go from
that position.
Maybe this means you need a strain sensor on the rope (or
equivalently, a torque sensor on the rope wheel before it is attached
to the motor shaft). However, I can't help feeling it should be
possible to obtain equivalent information from the position and speed
of the shaft itself. That is, since the torque being applied by the
motor at any time is known, and the position of the shaft (hence its
velocity and acceleration, by differentiation) is known, the torque
imposed by the rope must be uniquely determinable.
.
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