Re: Plotting the Curves of Coriolis, Einstein, and NoEinstein (is Copyrighted.)



In sci.physics, PD
<TheDraperFamily@xxxxxxxxx>
wrote
on Thu, 6 Mar 2008 08:38:27 -0800 (PST)
<e03e5e08-2375-48e9-9b74-929bd6715161@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:
On Mar 6, 9:44 am, The Ghost In The Machine
<ew...@xxxxxxxxxxxxxxxxxxxxxxx> wrote:
In sci.physics, PD
<TheDraperFam...@xxxxxxxxx>
 wrote
on Thu, 6 Mar 2008 05:35:55 -0800 (PST)
<00968030-3bfa-4cdb-8be2-3e9937551...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:

On Mar 6, 12:19 am, "Androcles" <Headmas...@xxxxxxxxxxxxxxxx> wrote:
"Randy Poe" <poespam-t...@xxxxxxxxx> wrote in message

news:c0aa1d28-859a-455c-be7c-9efe4ca93761@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
| On Mar 6, 12:21 am, NoEinstein <noeinst...@xxxxxxxxxxxxx> wrote:
| >      Einstein's special relativity equation implies that the vector E
|
| It's a scalar.

HAHAHAHA!
Idiot!

Why would you laugh at energy being a scalar? Idiot!

PD

Since E = Fd in most scalar formulations, but F and d are
both vectors in most 3-D problems, one has to ask what
the operator is.

Best I can do is note that a transverse force (F dot d = 0)
won't move the item in the indicated direction; therefore
E = F dot d would work but makes E a scalar.

In particular PE = - F dot d, or even better, PE = - int[ F dot ds],
or equivalently F = - grad (PE).

Of course, Androcles is so rusty on his mathematics that the nail
holding his diploma to the wall has corroded in two, so he'll likely
spout and fume without much meaningful content.

He's not the only one who's a little rusty; I've not done
grads since college. ;-)



This logic clearly won't work in AndrocleanPhysics(tm).
(I'm not sure how well it works in regular Newtonian physics. ;-) )

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