Re: Parabola,bernouli equation,Free energy
- From: "Gieniu" <warendag@xxxxxxxxx>
- Date: Mon, 10 Mar 2008 06:24:59 GMT
"Gieniu" <warendag@xxxxxxxxx> wrote in message
news:QjXAj.72163$FO1.68814@xxxxxxxxxxx
Hiif h=H Ekin =ro SgHH/2=mgH/2
The straight tube is verticaly plunged in the water of sea
on the deep H.and long of this tube is H also.
The crossection of this tube is S
Both ends of this tube are open
The whole tube is filled of water.
To explane problem in the first we install a motopump on
the top of tube.
Nextly using of compressor ,water is removed from inside
of tube to outside of tube, to the sea.
The cmpressor does work W.
dW = Fdh
dW = ro SgHdh - roSghdh
W =ro Sg (Hh - hh/2) =Ekin
W =ro S(gHh -ghh/2)
W= ro Sg(H - h/2)h = Ekin -it is parabola
Using Bernouli principle ,we have:
the sum energy before crossection S of pipe is equal
sum of energy after this crossection.
mgH + mvv/2 = mgh/2 + mVV/2
mgH -mgh/2 = mVV/2 where v=0
ro SgHh -ro Sghh/2 = ro ShVV/2 = Ekin
ro Sg(H-h/2)h =Ekin it is also parabola
If h=0 and h=2H then Ekin =0
Using the motopump we can to transport this speedy water on haight h1with permanent velocity V=sqrt(gH),
above level of water in the sea
The work of motopump is equal w1=mgh1.,
and energy of the water in the same time is equal
W=mgH/2
Efficiency of system equal mgH/ mgh1
E.W.
.
- References:
- Parabola,bernouli equation,Free energy
- From: Gieniu
- Parabola,bernouli equation,Free energy
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