Re: Formula for Decelerating Light

On May 3, 1:15 pm, Michael Helland <mobyd...@xxxxxxxxx> wrote:
On May 3, 1:26 pm, jjs...@xxxxxxxxx wrote:



On May 3, 5:58 am, Michael Helland <mobyd...@xxxxxxxxx> wrote:

On May 2, 11:20 pm, jjs...@xxxxxxxxx wrote:

On May 3, 12:26 am, MichaelHelland<mobyd...@xxxxxxxxx> wrote:
<snip>

Show a derivation of your formula....

Instead of calculating a Hubble distance, calculate Hubble time
instead.

Expansion time and deceleration time are identical, because f  = 1/t.

Unlike Uncle Al I am interested to know where you dug these numbers up
from
v = 1 - (t * (20* 1.05702341) * 10^-13)  like the 20 and 1.05702341....

The Hubble's Parameter is about 20 km / Mly

That's the 20, and the 1.057 * 10^-13 converts km into light years.

I think I fucked up, because it should be in million light years.

So that would really be 10^-19?

So basically you have no idea what you are doing and you couldn't even
be bothered to do a units check.
.

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