Re: Formula for Decelerating Light

Michael Helland wrote:
On May 3, 1:26 pm, jjs...@xxxxxxxxx wrote:
On May 3, 5:58 am, Michael Helland <mobyd...@xxxxxxxxx> wrote:

On May 2, 11:20 pm, jjs...@xxxxxxxxx wrote:
On May 3, 12:26 am, MichaelHelland<mobyd...@xxxxxxxxx> wrote:
<snip>
Show a derivation of your formula....
Instead of calculating a Hubble distance, calculate Hubble time
instead.
Expansion time and deceleration time are identical, because f = 1/t.
Unlike Uncle Al I am interested to know where you dug these numbers up
from
v = 1 - (t * (20* 1.05702341) * 10^-13) like the 20 and 1.05702341...


The Hubble's Parameter is about 20 km / Mly

That's the 20, and the 1.057 * 10^-13 converts km into light years.

I think I fucked up, because it should be in million light years.

So that would really be 10^-19?


I meant: http://www.google.com/search?hl=en&safe=off&q=71+km%2Fs%2FMpc+*+2+*+10%5E7+light-years
.

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