Re: Formula for Decelerating Light

On May 5, 1:12 pm, jjs...@xxxxxxxxx wrote:
On May 5, 1:07 pm, Michael Helland <mobyd...@xxxxxxxxx> wrote:

Think of Hubble Law, and think of Hubble's parameter as a parameter of
expansion.

You can redefine the expansion parameter in to a deceleration
parameter, with the units km/s^2, then you have:

v = c - (t * H)

Read this:http://en.wikipedia.org/wiki/Hubble_parameter#Derivation_of_the_Hubbl...

Hubbles law and parameter are a bit more complex then that.


Point is Hubble's law calculates the recessional velocity.

It could be reinterpreted to calculate decelerated velocity, then
Hubble's parameter would be in the units of deceleration and something
like this would work:

v = c - (t * H)
.