Re: Rotational Mechanics

From: Ray Vickson <RGVickson@xxxxxxx>
Date: Thu, 15 May 2008 10:51:14 -0700 (PDT)

On May 15, 8:55 am, hubert.ruyp...@xxxxxxxxx wrote:

A car is driving on a circular race track with a diameter of 1 mile
and has a contant acceleration of 4,61 ft/s². The magnitude an
direction of the acceleration vector of the car 15 seconds after
starting is asked.

The book gives as answer 4,95 ft/s² and 57°

According to my calculation this has to be 4,95 ft/s² but 68°.

Can some-one help me out ?

Show your work. That way, people will be in a better position to help
you.

R.G. Vickson
.

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Re: Rotational Mechanics
... A car is driving on a circular race track with a diameter of 1 mile ... and has a contant acceleration of 4,61 ft/s². ...
(sci.physics)
Rotational Mechanics
... A car is driving on a circular race track with a diameter of 1 mile ... and has a contant acceleration of 4,61 ft/s². ...
(sci.physics)
Re: Rotational Mechanics
... direction of the acceleration vector of the car 15 seconds after ... So the angle of the acceleration vector is given as tan^a/a ...
(sci.physics)