Re: Water wave question..

On Jul 3, 2:21 pm, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
PD wrote:
On Jul 3, 1:57 pm, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
PD wrote:
On Jul 3, 10:21 am, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
PD wrote:
On Jul 3, 9:41 am, "Spaceman"
<space...@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
PD wrote:
On Jul 3, 9:10 am, "Spaceman"
<space...@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
PD wrote:
On Jul 2, 4:53 pm, "Spaceman"
<space...@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
If a 1 centimeter sphere that floats in water
half way normally just sitting there and has a mass of 1gram,
were dropped from 2 centimeters above the water...
What would the wave length from the first peak to the second
peak be, and what would the height of that peak also be?

You almost have enough information, but you also need the
depth of the water. Do you know why?

Oops
yup gotta have depth.

Do you know why?

Yes,

BS, but never mind....

Only BS in your head because you always have something
to make up about my knowledge limits.

but that is not the issue here so you can ignore
what I know since the answer has nothing to do with what I know
about the situation except the facts I have given already.
The measurements.
Do you have an answer or are you going to just twist away
for ever as usual?

I'm not twisting, just taking my time. Are you in a hurry? Is
this a problem you have to solve soon otherwise you'll have to
give someone's money back?

So, the way to solve this is to find the frequency of the
oscillation of the ball in the water and the speed of wave
propagation in the water. And then the distance between the
ripples will be the speed of propagation, divided by the
frequency. Do you agree? Do you know how to do it yet? If you do,
what do you think is the next step?

Yes that is what I am looking for and..
I am only looking for the first wave set created (wave 1 and 2)
calculated measurements.
I am trying to find someone to do this idependantly of my
"experiment" If I tell you anything about what I figured, it would
not be independant at all.
You choose YOUR next step.

OK, how about we take turns? I'll take a step, and then you take a
step. That's called collaboration. I have an idea how to get the
whole way there, so when you take a step, I'll let you know whether
that's the direction I had in mind, and you can do the same for me.

I've already done a step, but I'll take another one just in the
spirit of good will.
The frequency of a floating object that bobs up and down in the
water is given by Hooke's law, where the restoring force is the
imbalance between the buoyancy force and the weight.

In equilbrium, the buoyancy force equals the weight:
d_obj * g * V_obj = d_liq * g * V_sbm
where d_obj = density of the object
d_liq = density of liquid
V_obj = volume of object
V_sbm = volume submerged

Since you want the sphere to be halfway submerged in equilibrium,
for small oscillations, we can take the belly band of the sphere to
be roughly a cylinder, which should be good enough for the
calculation we need to do.

OK, so far? So what's the next step?

For you to use all that and give an actual answer instead
of a twist around the final answer of the question given.
The only "step" wanted was the final answer.
It looks like I will have to make the question 10 pages
long so you will grasp it to be able to answer it.

So if I told you the answer was "6", how would you know how that
answer was arrived at? How would you have any basis for knowing
whether it's right?

If you told me the answer was 6 I would know you do not have a
complete answer.

Ah, quite so. So if I told you my answer was 6 cm and 0.4 cm, how
would you know how that answer was arrived at or whether it is at all
close to correct?

you have no units and are missing the other half of the
question.
and yet again your no answer is proof of the fighting of giving
an answer at all.

I know you haven't done the experimental test, because you don't have
a 1 cm ball with a mass of 1 gram that floats halfway in the water.

Even if that were the fact about the ball not floating (but it is not) you
are still just
not answering at all.
That is the typicle relativist way, I should have remembered.
my bad..
No answer needed now PD,
new question "fixed" to not include the need for the floating at all.
Will you answer that one, or just twist all over the place again?
LOL

--
James M Driscoll Jr
Spaceman

.

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