Re: Paths against gravity and using gravity vs energy used


"Spaceman" <spaceman@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:z8ydnWsg8fC_U_LVnZ2dnUVZ_uidnZ2d@xxxxxxxxxxxxxx
Two paths are created for going over a mountian.

One path (path D for direct route) is a straight line to the top
and a straight line to the bottom on the other side.
Another path (path C for curved) is a curved path to the top
and a curved path to the bottom on the other side.
The distance bewteen the start of the paths to the end of
them is the same and we can use a tunnel to prove such
of course.
So...
What path would need more final energy use to follow?
:)


--
James M Driscoll Jr
Spaceman


It takes the same amount of energy whichever route is taken...

E = m * g * (Height of end - height of start).

Assumptions:

1) The object traversing the parth is 100% efficient.
2) We can ignore secondary effects such as the varaition in local gravity
due to the mountain and the like.




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