Re: The problems with a "constant" speed
- From: "Greg Neill" <gneillREM@xxxxxxxxxxxxxxx>
- Date: Wed, 9 Jul 2008 15:35:16 -0400
"Spaceman" <spaceman@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:I6CdnSnrc6m5kejVnZ2dnUVZ_sbinZ2d@xxxxxxxxxxx
Greg Neill wrote:
"Spaceman" <spaceman@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
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PD wrote:
On Jul 9, 11:21 am, "Spaceman"
<space...@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
So,
You say if a light is at the back of the starship on the inside
and the starship travels at 0.6c that it will not do c to make
it to the front, making an off ship observer measure the
speed to be 1.6c?
It would not be measured at 1.6c. And in fact it IS not measured to
be
1.6c. It IS measured to be c. In real experiments.
So you had a starship that traveled at 0.6c and turned
on a light at the back of the ship inside the ship and had
two observers measure the speed to be the same even
though one was outside the ship watching the ship
and one was inside the ship.
Michelson Morley experiment. No change in velocity
with the observer moving (Earth motion). No change
in velocity with source motion (proper velocities
of steller light sources).
So now MMX was a starship moving at 0.6c
It was an equivalent experiment.
LOL
MMX only proved light bounces just like
a ball would in a constant moving train.
Consider the source of the light. It was a moving
source. Consider the reciever, it was also moving.
Your bouncing ball analogy is okay. Do the math for
a ball entering a bouncing-ball mechanism like
the M&M experiment from the forward direction and
the sideward direction. In order for the bounce
times to show no difference (as the M&M experiment
found), you'll have to adjust the velocity of the
incoming ball to always be the same with respect to
the train.
no different than a "at rest" train.
Right. Train speed doesn't matter, the measured
speed of light will always be the same.
.
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