Re: Does Relativity generate more heat than light?

On 18 Jul, 05:59, The Ghost In The Machine
<ew...@xxxxxxxxxxxxxxxxxxxxxxx> wrote:
In sci.physics, Ian Parker
<ianpark...@xxxxxxxxx>
 wrote
on Wed, 16 Jul 2008 09:41:35 -0700 (PDT)
<f89586ff-e004-43b6-80d6-2f7649474...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:





On 16 Jul, 14:38, "Tom Potter" <t...@xxxxxxxxxxxx> wrote:
"The Ghost In The Machine" <ew...@xxxxxxxxxxxxxxxxxxxxxxx> wrote in messagenews:uu3vk5-l3m.ln1@xxxxxxxxxxxxxxxxxxxxxxxxxx

In sci.physics, Tom Potter
<t...@xxxxxxxxxxxx>
wrote
on Tue, 15 Jul 2008 19:23:05 +0800
<g5i1se$62...@xxxxxxxx>:

"Eric Gisse" <jowr...@xxxxxxxxx> wrote in messagenews:fa49c195-92da-4344-8683-a3b2bef2ce49@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On Jul 13, 2:05 am, Tom Potter <tdp1...@xxxxxxxxx> wrote:
On Jul 13, 7:34 pm, Eric Gisse <jowr...@xxxxxxxxx> wrote:
On Jul 13, 2:25 am,Tom Potter<tdp1...@xxxxxxxxx> wrote:

Can I take your post to mean that you are
incapable of using General Relativity
to compute just ONE of the many things
that Newton computed hundreds of years ago.

Since I explicitly said that GR replicates all of Newton, no you
cannot.

Don't run and hide Gisse.

You claim General Relativity
is a useful and viable tool,
and that you are proficient in its' use.

General Relativity is entirely useless if one cannot
understand its core principles.  GR can be summed up
in one equation:

T = G

however, that equation involves tensors, unit conversions,
and a whole slew of concepts that I'd frankly have to
study in detail, and of course T and G are shorthands.

Good start Ghost!

Now why don't you expand that T = G
one step at a time,

and show how General Relativity
can be used to compute just ONE of the
many tides that Newton computed centuries ago,

to show the ignorant folks just how much more useful
and powerful GTR is than the old Newton model.

--
Tom Potter

http://www.geocities.com/tdp1001/index.htmlhttp://notsocrazyideas.blo....Hide quoted text -

Very simple. Classical Physics is the first term of A Taylor
expansion. This is shown in any standard text book on the subject.
This is true of both Special and General Relativity.

That's fine, but one has to generate the expansion.  You've
only documented the final step of a rather long process, at
least for me (others who already know tensors might have
an easier time of it).

You are of course correct AFAIK; a simple SR example involves

E = gamma * m c^2

It turns out that gamma = 1/sqrt(1-v^2/c^2)
results in

E = m c^2 * (1 + (1/2)v^2/c^2 + (3/8)v^4/c^4 + ...)
= m c^2 + 1/2 m v^2 + 3/8 m v^4/c^2 + ...

Note the second term; look familiar? :-)

However, I'm not that knowledgable about tensors.



In other words simply use the first term if we are moving slowly/ in a
weak field.

As I said ALL the textbooks fully explain this. I just don't know why
this is coming out. Well I do ... but

  - Ian Parker

--
#191, ewi...@xxxxxxxxxxxxx
Useless C++ Programming Idea #889123:
std::vector<...> v; for(int i = 0; i < v.size(); i++) v.erase(v.begin() + i);
** Posted fromhttp://www.teranews.com**- Hide quoted text -

Not really T has a number of terms which can easily be identified in
weak fields. The most intense field is straightforward Newtonian
Gravity. Now we want d2x/dt^2 = g. I can say this without loss of
generality as we can always rotate our coordinate system to the
direction of gravitational field. So far so good.

If a disc is spun we now get off diagonal terms in T. This is what ESA
has done fairly recently. The result - youv'e guessed it confirmation
of GR. This is now a departure from Newton.


- Ian Parker
.

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