Re: The opposing rockets and the box

"Spaceman" <spaceman@xxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:e4mdnbOu3sHhhxjVnZ2dnUVZ_jqdnZ2d@xxxxxxxxxxx

You removed the M for no reason at all.
You made it basically dissapear from the problem
without even knowing where you went wrong.
For some stupid ass reason you made m*v
hit a larger mass and still stay as m*v again even though
it combined with a larger mass.
Are you really that dense?

You have m*v = v*m/(M + m)
You are truly lost.

That is not what I wrote. I wrote v2 = v*m/(M + m).
That's the velocity of the combined masses following
the collision.


If m = 30 and M = 100
You have 10* 30 = 30*10/(100 + 30)
Why you can just multiply the (M +m) for no reason to the v2 is
amazing that you would try to pull such *** off at all..

So James, you want a concrete example with numbers.
Okay, let's follow your suggestion. I presume in the
above you meant to say that:

M = 100 kg
m = 30 kg
v1 = 10 m/s the initial velocity of mass m

Mass m impacts mass M which is initially at rest. For
convenience we will assume that mass m is initially
travelling along the x-axis in the positive direction
in our chosen frame of reference. Mass m sticks to
mass M in the collision (inelastic collision).

What, in your view, is the resulting velocity of the
combined masses after collision?
.

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