Re: Geometrical interpretation of c^2

On Jul 20, 11:22 am, cjcountess <cjcount...@xxxxxxxxx> wrote:
Hello Autymn D.C.
This is Conrad
Did you see the geometry? When two vectors of motion are equal and
perpendicular to each other they counter balance each other as a
centripetal / centrifugal force balance, to create circular motion.
Circular motion can be considered velocity squared if one takes a
horizontal vector and multiply it by a right angled vertical vector.

No, their resultand is the diadacton. (You say "diagonal".) In
circular motion the lone v-vector is tangent and oscillatory in time.

This is analogous to taking a line of one inch and multiplying it by a
line of one inch in right angle direction to create a square inch. And
furthermore if one takes the trajectory a projectile would follow if
it follows an arc from beginning of horizontal line to end of vertical
line it would be a 90 degree arc which if constant would be a circle.

so¿

This is new stuff and so I can see why you may not see. It is taught
in schools that vectors are added not multiplied and so following this
strictly it will not lead to the conclusion that I came to. This might
indicate a quantum change in the math describing vectors that
corresponds to the quantum change in the wave as it changes into a

Vectors do both. But the cc in E=mcc is a linear square in time, not
a rectangular square in span. Your maths suck.

-Aut
.

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