Re: Propellantless propulsion fun 3 (recirculative propelant)

Greg Neill wrote:
Sorry, I don't get your point. KE is simply (1/2)*m*v^2
where m is whatever mass is involved. What is
calculating the kinetic energy going to accomplish
here?

It is going to show you that it will take more
kinetic energy to stop the larger mass then it
took to "move" the larger mass.
Sheesh Greg.


Anyways, if you want the kinetic energy of the launched
ball it's (1/2)*m*v^2. If you want the kinetic energy
of the ball and object after impact it's

(1/2)*(M + m)*v2^2
= (1/2)*(M + m)*[v*m/(M + m)]^2
= (1/2)*m^2*v^2*/(M + m)

So it's smaller than the kinetic energy of the ball alone
was by a factor of m/(M + m). Again, kinetic energy is
*not* a conserved quantity in general.

So now you think the ball getting stuck in the large mass
will violate the conservation of energy.
LOL

--
James M Driscoll Jr
Spaceman





.

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