Re: Twin Fallacy revisited

Igor wrote:
On Jul 22, 12:46 pm, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
Strich 9 wrote:
The twin paradox has been analyzed many times, and many answers are
given. Dr. Parker has pointed to the multiplicity of the answers as
proof of its underlying error.

The standard answer brings in a new set of rules. While the paradox
is posited in the frameword of Special Relativity, the solution uses
concepts in General Relativity. "The stay at home twin experiences
no acceleration, and ages faster than the travelling twin, who
experiences accelerations". That was also how Einstein squirmed
through the solution. Not much of an answer if you ask me. But this
is the answer taught in physics schools, from MIT to CIT. Is it
correct? Of course not! Can I prove it? Of course!

Thus I posit the *_David_Twin_Paradox_*:

TWINS A AND B LEAVE TWO PLANETS AND TRAVEL AT EQUAL CONSTANT
VELOCITY TOWARDS EACH OTHER AT TOTAL RELATIVE VELOCITY V. TWIN A
SEES B MOVING TOWARDS HIM AND AGING SLOWER, AND VICE VERSA. WHEN
THEY FINALLY MEET, WHO IS YOUNGER?

Relativity analyses tells us both are younger. Since the
accelerations are equal, if any, then these cancel out. Still, one
sees the other as aging slower!

The common sense answer is that both age normally and are equal when
they meet.

This is probably the simplest proof of the failing of Relativity.

Both clocks will "change" equally from the motions incurred causing
the clock malfunctions to be "equal".
A third clock of course will show that both the traveling clocks
are still wrong.
Relativists hate third clocks.
:)


Nonsense. The relativistic triplet case works just fine:

http://sheol.org/throopw/sr-twin-01.html

Now, I know you'll never understand it, but there it is.

LOL
All based upon a clock malfunction.
http://www.hyperdeath.co.uk/spaceman/message.html


--
James M Driscoll Jr
Spaceman



.

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