Re: KE = ½ mv^2 is disproved in a new falling object impact test.
- From: Puppet_Sock <puppet_sock@xxxxxxxxxxx>
- Date: Tue, 19 Aug 2008 11:53:09 -0700 (PDT)
On Aug 16, 9:36 pm, NoEinstein <noeinst...@xxxxxxxxxxxxx> wrote:
[snip]
Today, I ran a simple KE test. I dropped a ¾” dia. chrome steel ball
from a height of 3.3684 feet into a small flower pot full of just-
mixed artclay.
You expect people to believe you measured the height you
dropped this ball from to five significant digits?
Clearly you are some mixture of stupid, a liar, a troll, and insane.
That ball sank in close to its ‘equator’.
And you then expect people to accept "close to" as a measure
of penetration.
Clearly you are some mixture of stupid, a liar, a troll, and insane.
I immediately went up my outdoor staircase and dropped a ¾” dia. PTFE (a
heavy fluoroplastic ball, weighing .2807 times as much as the chrome
steel ball), from an exact height of 12 feet. The KE value should be .
10469323 for each ball. Note: 12 feet of drop = .745944d, where d =
16.087 feet, the distance of fall in one second. The time of fall is .
86368 seconds for the lighter ball.
It would appear to be all of the above. You have reported 8
significant
digits for KE, but with no units. And you expect people to believe you
have *measured* the time of fall of this ball to five significant
digits.
At some point you should consider returning to public school
and completing your arithmetic lessons. You are a clue free zone.
Socks
.
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