Re: Information transfer without energy transfer ?

On Mar 27, 2:24 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:
Yes, OK, I'm with you so far.

Really, not kidding ?
Okay, now I'm gonna translate my proposal the best I can,
step by step, and we should discuss any divergence
of opinion as we did before, until we found it reasonnable,
then we sould proceed to the next step.
The translation will take some time, tough.



On Mar 27, 8:06 am, 5...@xxxxxxx wrote:
I already have good books on quantum physics.
My proposal does not concern entangled states
of several particles, there is only one photon involved.

Here is a short description of what I mean :http://powerdown.free.fr/tx/

In this particular case, I *know* that this the
standard interpretation of quantum mechanics.

The point is : no direction in space is determined
at the moment the photon is emitted from the source.
No localization of the photon is available until it is measured.
And the wavefunction is not a surface of energy,
it is a spherical wave of probability
( sum of potentialities written as orthogonal bases )
that will resolve in only one of those potentialities
at the time a measure is made.
At this moment, the wavefunction collapses, and the photon is
localized with 100% certainity where the measure has been made.

This is what I would like both of us to agree.

Yes, OK, I'm with you so far.





On Mar 27, 1:09 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:

I think the first thing you need to read up on are:
- what quantum states are, and how they are delineated by certain
(quantum) numbers -- that's why they are called quantum states in the
first place
- what quantum degeneracy means, and how two states can satisfy the
same preparation conditions.
- what superposition means in the case of degenerate quantum states.
- what happens to that degeneracy at the point of observation.

I assume I am ... so, any detector lying at the surface of the
spherical wave
(which can be pretty large) has the same (tiny) chance to catch the
photon.

On 26 mar, 23:34, PD <TheDraperFam...@xxxxxxxxx> wrote:

On Mar 26, 4:48 pm, 5...@xxxxxxx wrote:
The photon is in whatever quantum state it pleased,
providing its wavefunction travels along the straight line.
A photon is emitted at point S : then its wavefunction is a
superposition of the two possible directions : towards E and R ..

No, this is not correct.
How is this state prepared?

Do not confuse a scenario with two possibilities as being a
wavefunction.- Hide quoted text -

- Show quoted text -- Hide quoted text -

- Show quoted text -- Hide quoted text -

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.

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