Re: Do dark matter calculations make the stupid assumption that all mass is at the center of the galaxy?



On May 23, 10:35 pm, Jim Black <trams...@xxxxxxxxx> wrote:
frankli...@xxxxxxxxx wrote:
It would appear that the force of gravity within a ring of matter is
zero:

That is wrong.  It is true for a spherical shell, but not for a
circular ring.

http://galileo.phys.virginia.edu/classes/152.mf1i.spring02/GravField.htm

And that link does not support the assertion.

--
Jim E. Black

under:

Gravitational Field from a Ring of Mass

The formula for force on P depends on x, the distance away from the
plane of the ring. If x is zero such that the particle is within the
plane of ring, the numerator becomes zero and therefore the force for
a particle within the plane of the ring (as would be the case for a
galaxy), the force is zero. Is this not correct? Therefore for the
case of calculating the force on a star within the galactic disk, the
force is zero for mass outside of the orbit.

Of course, I would still like to see something better than a paper
napkin calculation showing that dark matter actually exists. I have
seen references indicating that if you do take into account the real
mass distribution of galaxies, that the rotational differences can be
explained. I would find this far more likely than the existence of
"dark matter". Therefore, no dark matter is necessary.


.



Relevant Pages

  • Re: An infinite number question
    ... If you exclude 0, the remaining numbers form a group ... A set with both addition and multiplication is a ring, ... If the set is a cyclic group under addition, as would be the infinite ... division except by zero is possible. ...
    (talk.origins)
  • Re: Can you explain prime force/energy & matter?
    ... >>a photon, because infinite energy is not available. ... Zero is zero. ... step up to spinning your ring (like ... So if we continue to hold the precession at ...
    (sci.physics)
  • Re: Gravity Inside A Cylinder
    ... Binney and Tremaine I find assuming a zero thickness ring ... The net force in the system is zero when the sun is located ... for all positions within the ring plane except the center. ...
    (sci.physics)
  • Re: An uncountable countable set
    ... think the absolute minimal set of axioms: ... semigroup under multiplication, distributive law), you have (for any x, ... y, in the ring): ... unless it is simply zero. ...
    (sci.math)
  • Re: Poles an Zeros
    ... First, you have to wrap your mind around a plane that represents all possible frequencies in two dimensions, called the S plane. ... A zero frequency, representing DC, is the origin. ... The S plane frequency representation is based completely on representing the signals and responses as complex exponentials (e raised to an exponent with real and imaginary parts, representing the two dimensions of the S plane. ...
    (sci.electronics.basics)

Loading