Re: Shell theorem vs. Black hole
- From: "Y.Porat" <y.y.porat@xxxxxxxxx>
- Date: Mon, 29 Jun 2009 22:14:08 -0700 (PDT)
On Jun 30, 3:23 am, Khattak <zarm...@xxxxxxxxx> wrote:
Shell theoremhttp://en.wikipedia.org/wiki/Shell_theorem
If the body is a spherically symmetric shell (i.e. a hollow ball), no
gravitational force is exerted by the shell on any object inside,
regardless of the object's location within the shell.
Black holehttp://en.wikipedia.org/wiki/Black_hole
In general relativity, a black hole is a region of space in which the
gravitational field is so powerful that nothing, including light, can
escape its pull
“As ring is also treated as shell in math/physics”
So can I ask a question why is there disagreement?
------------------------
take most of randomly chosen points
inside a ball
all of them will not have the same amount of mass
in all directions to make a balance.
iow
there is not balance of gravity
in most points in a ball
(done by the ball mass itself !!)
ATB
Y.Porat
-------------------------
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