Re: Levers increase force?



jbriggs444 wrote:
On Dec 23, 9:25 am, Peter <Poakfi...@xxxxxxx> wrote:
On Dec 22, 9:18 pm, Sam Wormley <sworml...@xxxxxxxxx> wrote:





On 12/22/09 7:47 PM, Peter wrote:
On Dec 22, 8:39 pm, Sam Wormley<sworml...@xxxxxxxxx> wrote:
On 12/22/09 6:59 PM, Peter wrote:
On Dec 22, 6:53 pm, Sam Wormley<sworml...@xxxxxxxxx> wrote:
On 12/22/09 4:57 PM, Peter wrote:
Force F = ma; the force that gives a mass m an accelerations a, and
the force that gives a mass 1000m an acceleration a/1000, are equal,
because ma = 1000m(a/1000)l, no?
Did you look over:
http://hyperphysics.phy-astr.gsu.edu/HBASE/Mechanics/lever.html
Yes, I did. It seems they have it wrong there.
Can you articulate the section that is wrong, for my benefit?
Thanks.
"With a lever, one can obtain a multiplication of force,"
That is not correct.
Let me put back a little context, "The lever is one of the
so-called "simple machines" from which many more complex
machines are derived. With a lever, one can obtain a
multiplication of force, but of course not a multiplication
of energy. The multiplication of force can be seen to arise
from the equilibrium of torques..."
I refer the reader to the accompanying diagram at
http://hyperphysics.phy-astr.gsu.edu/HBASE/Mechanics/lever.htmlhttp:/...
Peter, I would recommend getting a crowbar and dismantling something
with it, thinking about the amount of force exerted at the short end.
You do know what force is, do you not?- Hide quoted text -
- Show quoted text -
Sam, force equals mass times acceleration, by definition, i.e., F = dp/
dt = ma.

No. That is not correct. That's not what Newton's second law states.

Newton's second law says that

F = ma

Where F is the TOTAL force on an object
and m is the mass of that object
and a is the acceleration of that object's center of gravity.

You don't get to point at a single force, call it F and say that F=ma
for that
single force acting alone.

<snip> Nitpick. That's why the simple algebraic expression, F=ma,
is not quite correct, and is confusing to non-physics types.
Sigma should be mentioned or something when writing the equation.

/BAH
.



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