Re: Heavy Lift Design for Mining/Cargo Propulsion
- From: Willie.Mookie@xxxxxxxxx
- Date: Tue, 22 Apr 2008 10:34:25 -0700 (PDT)
The energy applied to a propellant determines how fast it can be made
to move.
E = 1/2 m V^2
The rate at which propellant is moved through the system determines
the thrust
F = dm/dt * V
The determines the power of the engine
Power = 1/2 * dm/dt * V^2
The pump power is given by the dynamic pressure times mass flow rate
Pump Power = pressure *dm/dt * factor
and dynamic pressure scales with chamber velocity
Dynamic Pressure = 1/2 rho V^2
You can see that the pump power scales with the engine power. So, if
you inject propellant under zero pressure (when the engine is off) you
save considerable power.
In a continuous rocket these are continuous functions. In a pulse
rocket, these occur in pulses, which are averaged over time. This on
again off again operation lowers the thrust for a given thrust
structure and adds the need to smooth the pulses with some sort of
momentum transfer device.
So, why do it?
Because it reduces heat handling problems as well as pump or injector
power and weight and cost.
When you pump something against a pressure, that takes power too as
shown. Subtracting from the power of your engine. Even if you're
shooting ions with an ion beam into a magnetic containment of other
ions, speeding those ions up to the speed needed takes energy. Its
the same process - and the same energetic relations. I call them all
pumps, even if they look more like an ion gun at the back of a CRT
display and not a typical centrifugal turbopump.
So, when you get really really high pressures you get really really
high pump energy - and that means costly, heavy, complex pumps that do
not scale well with increasing performance. Which means at higher
energies, it makes sense to dispense with pumps altogether, and put up
with heavy thrust structures and momentum transfer structures - while
you're working on improved continuous or high frequency versions.
http://en.wikipedia.org/wiki/Pulse_detonation_engine
http://en.wikipedia.org/wiki/Nuclear_pulse_propulsion
http://en.wikipedia.org/wiki/Project_Orion_%28nuclear_propulsion%29
This derives from the dynamic pressure of a highly energetic gas or
plasma.
Pulse rocket: (no pump energy)
TNT : 1 ton per ton
4.184 GJ
2.9 km/sec
U235: 3 million tons per ton
12,052,000 GJ
5,022.9 km/sec
Li6D: 60 million tons per ton
251,040,000 GJ
22,463.3 km/sec
Continuous Rocket -
dynamic pressure with plasma density equal to 1 kg/m3
Solid: 2.9 km/sec
4.2 megapascals
U235: 5,022.9 km/sec
12.6 million megapascals
Li6D: 22,464.4 km/sec
252.3 million megapascals
By the way, we can see how much easier it is to contain a useful
plasma of uranium or plutonium than it is to contain a useful plasma
of fusor material...
Now, to get a ton of thrust from each engine requires
F = dm/dt * V ---> dm/dt = 9,820 / V
Solid: 3.38 kg/sec
U235: 1.96 grams/sec
Li6D: 0.44 grams/sec
The power of the engine is given by the mass flow rate times gas
velocity. So, for our engine that produces one metric ton of thrust
we have
P = 1/2 * dm/dt * V^2
Solid: 14.2 megawatts.
U235: 24.7 gigawatts
Li6D: 111.0 gigawatts
In a continuous engine we have to overcome the dynamic pressure for
each kg we inject pump or otherwise insert in our engine. For the
solid, to make things comparable, we imagine feeding a rod of solid
material into the combustion chamber at the burn rate required. Its
easy to see that driving this rod forward requires power - even though
its not a turbopump it is a sort of solid pump. Similarly, a magnetic
containment for U235 that 'leaks' a stream of actinide series products
needs new U235 this is easily added by shooting small pellets into
the containment with enough speed to overcome the pressure to arrive
inside the chamber. Kicking the pellets up to speed requires energy,
typically 1% of the energy produced by the engine.
Solid: 142 kilowatts - 'pump' power
U235: 247 megawatts - 'pump' power
Li6D: 1.11 gigawatts -- 'pump' power
Now a 1.11 gigawatt pump is a pretty impressive piece of engineering.
The circulating power in a fusion rocket producing just one ton of
thrust requires as much energy as a full scale nuclear power plant -
which typically weighs far more than a ton.
So, to get reasonable thrust to weights at these high performances
with materials and techniques we know how to use today - a pulsed
system is recommended. This doesn't mean you don't continue research
on continuous systems, but you don't wait on continuous systems
either.
The thrust to weight of most chemical engines is about 70 pounds of
thrust for each pound of engine. The thrust to weight of a nuclear
light bulb engine, or a fusion variation of it, is less than 1 to 1 -
due to the weight and power levels needed for the pumps and heat
handling.
Pulsed systems don't have much injector or pump energy. That's
because they're not working against any chamber pressure. They inject
new pulse units when the engine has cleared of the last pulse - or
nearly so - and so, these injector systems can be quite modest in
their power requirements.
Heat transfer is another problem with high performance engines.
Temperature is a measure of energy. The velocity of a plasma which is
proportoinal to the exhaust speed of the engine is proportional to the
square root of the temp
http://en.wikipedia.org/wiki/Thermodynamic_temperature
This doesn't change. A continuous engine has to handle heat
diffusing through it
http://en.wikipedia.org/wiki/Heat_conduction
An intermittent engine can transfer momentum from a hot plasma to a
thrust structure (either magnetic, electrostatic or physical) before
the plasma cools - or transfers a lot of energy out of the plasma
(either by radiation or conduction) to other surfaces. If surfaces
get hot the intermittent engine can slow pulse rate to keep them
cool. A very robust system.
As I've mentioned elsewhere, I am doing a detailed engineering and
numerical analysis for a fission free Li6D with D+T trigger - and HF
frangible laser initiator - using a 'magnetic blanket' design with
multiple-detonation chambers, all venting to a common magnetic
exhaust. The resulting spacecraft is a spherical design with a super
magnet just below the equator, and a plug sticking out of the south
pole of the ball. There are 8 detonation channels feeding into the
common thrust chamber. Eight chambers and a single magnetic nozzle
to collimate the resulting plasma stream smooths out thrust without
excessive mass dedicated to momentum transfer. The rotating magnetic
field created by the plasma containment field changes, conserves
containment energy, and tapping the current flow between containment
fields charging and discharging, provides a simple source of AC power
while the engine is running.
The smallest version is 12 m in diameter and produces 1,100 metric
tons of thrust, masses 165 metric tons empty, carries 200 metric tons
of propellant, and up to 200 metric tons of payload. I modeled this
design on the Aires 1b moon shuttle, though the propulsion system is
far superior than that imagined for the movie 2001.
Exhaust speed exceeds 20,000 km/sec. At one gee thrust - generating
565 metric tons of thrust (5.55 MN)- the engine consumes 0.28 kg/sec
of propellant. Thrust is adjusted by adjusting pulse rate. Top speed
is 8,738 km/sec - divide by 4 to obtain a four boost distance at
constant gee. (2,184.6 km/sec per boost) This is maintained by
injecting 4.6 gram pulse units into the engine at a rate of 60 per
second - with each chamber cleared in less than 125 milliseconds. 450
pulse units are injected per minute into each chamber - with a 1/60th
second lag between adjacent chambers.
Thrust at one gee to reach the speed limit imposed by the propellant
takes 2.57 days or 61.7 hours - that distance is 242 million km per
leg 484 million km total distance.
This is a velocity limited system, so the relations between distance
and gee force are pretty simple.
Distances shorter than 484 million km distant, mean shorter boost
times, and the ship has legs for that. The Earth Moon system for
example has two planets separated by 0.38 million km - and this ship
takes less than 3.5 hours to jump from one body to the other at 1
gee. The ship can carry out 35 flights between these bodies before
refueling.
Mars varies from 58 million km distant to 378 million km distant. So,
again, the system described here can tool around the inner solar
system at one gee no problem.
The dwarf planet Ceres varies in distance from Earth from 264.7
million km to 564.7 million km. So, we're going beyond the range of
the vehicle at one gee.
No problem, lowering gee level in flight reduces propellant
consumption, and increases range, at the cost of lengthening trip
time.
The Jovian system for example varies in distance from the Earth in the
range 628.5 million km to 928.5 million km. Even so, the constant gee
system can get to Jupiter by reducing acceleration.
Say the acceleration is cut in half - that means it takes twice as
long to achieve a given velocity maximum at half way to have enough
fuel to return.
V = a * t = 2,184,600 m/sec = 4.91 m/sec/sec * t
t = 444,928.7 seconds = 5.15 days
this increases distance to reach this velocity
D = 1/2 * a * t^2
= 1/2 * 4.91 m/s/s * 444,928.7 ^ 2
= 485,995,600,545.4 meters
= 486 million km
Double this distance is 972 million km - which reaches Jupiter. Bring
provisions for 22 days plus however long you're going to stay in the
Jovian system.
What about a visit using this ship to Eris and its moon Dysmonia?
(although I like planet Xena - aka planet X)
It varies a distance from 14,355 million kilometers to 14,655 million
kilometers from Earth over the course of a year.
http://en.wikipedia.org/wiki/Eris_%28dwarf_planet%29
http://en.wikipedia.org/wiki/Kuiper_belt_objects
Can this ship make it there?
Sure! At lower gees. Lets say on a given day the half-way point
between Earth and Eris is 7,250 million km. Our top speed is still
2,184.6 km/sec per boost. So, we can figure out what are gee force
has to be to give us that distance
D = v^2 / (2a) -->
a = V^2 / (2D)
= (2,184,600)^2 / (2*7,250,000,000,000)
= 0.329 m/s/s
About 1/30th gee...
It will take 76.85 days to reach the half way point at this
acceleration, and another 76.85 days to arrive at Eris. It will take
153.7 days to return - about 10 months round trip. Less time than it
takes to fly to Mars and back with a chemical rocket system.
With a crew of 16 - 10 passengers in five staterooms - and 4 pilots -
with 2 stewards - sharing flight quarters up front - and a main deck
between the two - this flight will take 32 tons of consumables - 200
tons of propellant - and can carry 18 tons of personal effects - and
150 tons of scientific gear.
Again, a nuclear pulse fusion rocket built along the lines described -
even as small at a 12 m diameter ball (40 ft) carrying between 16 and
180 people, or up to 200 tons of cargo - would be what both Heinlein
and Clarke have described as the DC-3 of space!
A single ship tasked to Luna would transfer 400 tons of cargo and 180
people EVERY DAY to the moon. A single ship tasked to Mars would
transfer 200 tons of cargo and 90 people EVERY WEEK to Mars. A single
ship tasked to explore the outer solar system could do a significant
exploration EVERY YEAR OR LESS - to any object we can see from Earth
in our planetary system.
.
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