Re: Holm's method for multiple comparison??

"Thom" <t.s.baguley@xxxxxxxxxxx> wrote in news:1131032503.630565.229930
@g43g2000cwa.googlegroups.com:

> I'm pretty sure i=j which is the index number of the contrast. So in
> effect you use a per test alpha of familywise alpha/(n-i+1). So for 20
> tests you start with per test alpha/20 for the largest difference and
> alpha/19 for the next largest and so forth.
>
> Note that this looks like the Lazerlere (spelling) & Mulaik procedure
> which is equivalent to Holm, but more generic.
>
> Thom
>
>

Thanks Thom.

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Scott
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