Re: Testing the effects of multiple terms in a two- / three-way ANOVA
- From: Bruce Weaver <bweaver@xxxxxxxxxxxx>
- Date: Fri, 02 Mar 2007 15:12:25 -0500
madhu.balasubramanian@xxxxxxxxx wrote:
- Show quoted text -
Thanks very much for your reply. Thinking about it, option 2)
[SOS(<beta>) / DF(<beta>) + SOS(<alpha><beta>) / DF(<alpha><beta>)],
is not at all a mean, just sum of two means. By the way, what do you
mean by 'partitioned'.
I thought this terminology was pretty standard across disciplines. Perhaps I can explain by example. Here is a partitioning diagram for the sums of squares in a one-way ANOVA.
SS(Total)
/ \
/ \
/ \
SS(Between-groups) SS(Within-groups)
SS(Total) is partitioned into SS(Between-groups) and SS(Within-groups). Or putting it another way,
SS(Total) = SS(Between-groups) + SS(Within-groups)
You could do a similar partitioning diagram for the total degrees of freedom by substituting df for SS.
In a partitioning diagram for a (balanced) two-way ANOVA, I would change "groups" to "cells", and then further partition SS(Between-cells) into SS(A), SS(B), and SS(AxB).
--
Bruce Weaver
bweaver@xxxxxxxxxxxx
www.angelfire.com/wv/bwhomedir
.
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