Re: interval estimation of a parameter

From: Brendan Halpin <brendan.halpin@xxxxx>
Date: Wed, 19 Sep 2007 17:18:07 +0100

"albert.mills@xxxxxxxxxxxxxx" <albert.mills@xxxxxxxxxxxxxx> writes:

It's the same thing. Take this part of the probabilty statement:

x-1.96*sd< u < x+1.96*sd

Subtract x from the three terms:

-1.96*sd< u-x < +1.96*sd

Subtract u from the three terms:

-u-1.96*sd< -x < -u+1.96*sd

Multiply by -1 (note inequality reverses):

u+1.96*sd > x > u-1.96*sd

Brendan

--
Brendan Halpin, Department of Sociology, University of Limerick, Ireland
Tel: w +353-61-213147 f +353-61-202569 h +353-61-338562; Room F2-025 x 3147
mailto:brendan.halpin@xxxxx http://www.ul.ie/sociology/brendan.halpin.html
.

References:
- interval estimation of a parameter
  - From: albert.mills@xxxxxxxxxxxxxx

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