Re: statistics/probability problem

From: Mark Solinski (mark.solinski_at_sap.com)
Date: 08/25/04 

Date: 25 Aug 2004 17:56:37 GMT

"rakotor" <rakotor@free.fr> wrote in news:cghu1u$l9o$1@news.tiscali.fr:

> Elaine <Elainebagwell@bellsouth.net> a écrit dans le message :
> kcj141ez4zj4@legacy...
>> I am having trouble figuring out a probability question. (what set of
>> six numbers in which the mode, median, and the mean are the same. All
>> six numbers cannot be the same, however, two or more can be the same.)
>> Can anyone help me ?
>>
> for instance, if x1 and x2 are two non equal numbers, how can you choose
> in a simple manner x3, x4, x5 and x6?
>
>
>

Given x1 != x2 (or not):
  x1, x2,
  x3 = x4 = x5 = x2,
  x6 = x2 + (x2 - x1)