Re: calculus of conditional probability?
From: Alain Verghote (alainverghote_at_yahoo.fr)
Date: 08/28/04
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Date: Sat, 28 Aug 2004 15:36:22 +0000 (UTC)
On 27 Aug 04 21:15:03 -0400 (EDT), ames_kin wrote:
>Hello,
>
>I'm trying to figure out how to do integrals of a conditional
>probability. Does anyone have a textbook they can suggest for a bio
>student?
>
>let's say the integrals are like...
>
> /
> | dI P(E,I)p(E|I)
> /
>
>where P(E,I) is a measured levels of P for given E and I,
>and p(E|I) is a conditional probability.
>
>How do I go about solving soemthing like that and gain intuition as
to
>what it means?
>
>Sorry for newbie question.
>
>any help will be appreciated.
Dear Ames,
You'd better start with repartition function:F(x,y)=Prob(X<x,Y<y),
density f(x,y)=d^2/dx*dy (F(x,y) .R a rectangle abscissas a ,b
ordinates c,d then Prob((X,Y) in R)=int{a,b}[int{c,d} f(x,y)dx] dy.
with int{-infinity,+infinity} [int{-inf,+inf} f(x,y)dx]dy =1.
Hope your catch my 'writing'.
Density of x :f1(x)=int{-inf,+inf} f(x,y)dy and f1(x)*f2(y|x)=f(x,y),
Try to visualize on a plane :rectangles areas ,strips areas,
intersected strips areas ,and limits (very thin strips).
Be it useful,
Alain.
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