Re: Advanced Monty Hall Problem with N door and M cars

From: Jack (mrjack_2005_at_yahoo.com)
Date: 02/21/05 

Date: Mon, 21 Feb 2005 21:38:02 +0000 (UTC)

I promise you that this is not a homework.
And I actually calculated the probabilites ... but I am sure of them:

P(staying)=M/N

P(swtiching) = (M/N)*(N-1)/(N-2)

Do you think that is true.

On Mon, 21 Feb 2005 18:24:15 +0200, Anon. wrote:
>Jack wrote:
>> Hello Everybody,
>> I really need you help in solving an advanced Monty hall problem.
>> Assuming that we have N door with M of these door have cars behind
>> them and N-M of these door has $1 bill behind them.
>> Assuming that the player made an initial selection (she picked a
door
>> D1), now.... Monty open a door that has a $1 bill behind .... now
he
>> asks her, if she want to stay with her initial choice or if she
wants
>> to switch?
>>
>> What is the probability of winning if she stay with her choice?
Isn't
>> it P(winning if she stay with her inital decision) = M/N?
>>
>Yes.
>>
>> What is the probability of winning a car if she switched to
different
>> door?
>>
>If you understand the original Monty Hall problem, then you should be

>able to work this out. If necessary, just write down the different
>possibilities.
>
>I'm not giving you the answer - this might be homework.
>
>Bob
>
>--
>Bob O'Hara
>Department of Mathematics and Statistics
>P.O. Box 68 (Gustaf Hällströmin katu 2b)
>FIN-00014 University of Helsinki
>Finland
>
>Telephone: +358-9-191 51479
>Mobile: +358 50 599 0540
>Fax: +358-9-191 51400
>WWW: <a
href="http://www.RNI.Helsinki.FI/~boh/">http://www.RNI.Helsinki.FI/~boh/>
>Journal of Negative Results - EEB: www.jnr-eeb.org

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