Re: Variance components analysis in random effects ANOVA with one factor
- From: "Anon." <bob.ohara@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 12 Jan 2006 17:05:38 +0200
Carlo F. wrote:
Yes. This is also the ML solution, if ou have balanced data and assume normality.On Wed, 11 Jan 2006 21:22:21 +0200, Anon. wrote:
Thanks Bobfor your two messages.
My concern is exactly that: how to test that the assumptions holds ?
Particularly, I should somehow test that all the covariance between
the random effects ("tau"s) and between random "tau"s and
errors("epsilon"s) are zero. But how can I do it if I don't have any
experimental value for tau_i and epsilon_i,j ?
You can't. By the assumptions, E(epsilon_i.)=0, so tau_i is estmated assuming epsilon_i._bar=0 (this induces a covariance between the estimates, though).
Hi, bob.
So to recap, One way could be:
1) by the moment method applied to the model I get y.._bar=mu;
Yes. It makes sense that a point estimate forces epsilon_i._bar to zero: of course it is unlikely to be precisely that, but you can calulate confidence limits to see how far out you could be.2) On the ground of the weak law of large numbers I assume that the items in each levels , call it n, are big enough that the difference between E(epsilon) and epsilon_i._bar negligeable/ converge in probability. Or again I could invoke the method of the moments not to estimate E(epsilon) which I assumed equal zero, but "to force" epsilon_i._bar to zero. In this way, I get, for each of the i random effects tau(i=1..a), n realisations of the random effect tau_i, for each tau_i. tau_i_hat=y_i._bar - y_.._bar_bar (i=1..a);
3) At this point I can compute the residuals: e_ij=y_ij- tau_i_hat;
Yes.
Well, almost. The e_ij's are realisations of the same random variable, but the estimates depend on the estimate of tau_i. Alas, there's nothing you can do to change it.4) Now I can :
4a) Am I correct saying the following? " At the i-th level of tau, It is impossibile to test cov (tau_i, e_ij) =0. in fact, sample correlation between tau_i_hat and e_ij does not mean anything because e_ij are a set of single realisations of differrent random variables epsilon_ij and not n realisations of a single random variable. " So, this assumption will be not verified nor supported by any experimental evidence or reasoning. Correct ?
4b) plot of the residuals versus run order and autocorrelogram to support
idea of independence of the N=n*a random variables epsilon_ij
Yes, assuming run order makes some sort of sense scientifically.
4c) plot of the residuals versus levels and/or y_i_., that now, based onPlot against levels. You will also be able to spot outliers. One trick is to "jitter" the Levels, i.e. add/subtract a little bit, so that you move the ponts apart but it is still clear which level they are in. Or use boxplots.
1)+2) I can accept as "fitted" value. To see omoschedaschity and/or
patterns
4d) some Test on equal sigmas of the residuals. Here, now I envisage further doubts. but never mind.
Yes. The plots might be enough to tell you what's going on.
I would draw normal probability plots: they can show you what is going on, e.g. outliers or skewness. With enough data, you can get any test to be significant, but it may mean nothing in practice.4e) Normality: via Anderson Darling I rejected: so for further analyses (confidence interval, F-test), I need to thing something different or, at least for F-test invoke the robustness.
Have fun! There is no one algorithm for this sort of thing: there are a bunch of tools that you can use to help learn about the data. I then to favour the graphical ones because then I can see what the data is doing.In box-hunter-hunter, there is a quite different approach: I'll try to mix the two.
And what about the following:
Straight away from the model definition, it seems that the y_ij must be
with cov !=0 for same i or same j (see also Evgenii's paper). Thus, what
I've got at a certain level, say i', is that y_i'j with j=1..n are not
independant.
True:it's called the intra-class correlation.
Therefore all the y_ij are not independant. And what if the
autocorrelogram via acf() in R seems to say autocorrelations all close to
zero ? How would you interpret it ?
It would suggest that the tau_i's are all almost equal...
You should examine the autocorrelation of the residuals. The assumptions of independence are assumptions about the tau_i's and epsilon_ij's, not the y_ij's.
Bob
-- Bob O'Hara
Dept. of Mathematics and Statistics P.O. Box 68 (Gustaf Hällströmin katu 2b) FIN-00014 University of Helsinki Finland
Telephone: +358-9-191 51479 Mobile: +358 50 599 0540 Fax: +358-9-191 51400 WWW: http://www.RNI.Helsinki.FI/~boh/ Journal of Negative Results - EEB: http://www.jnr-eeb.org
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