Re: probability question
- From: "Andrew Schuyler" <aschuyler1@xxxxxxxxxx>
- Date: Sat, 25 Feb 2006 23:56:20 GMT
You are right again!
Thank Y
ou
""Luis A. Afonso"" <licas_@xxxxxxxxxxx> wrote in message
news:2239222.1140903096495.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxxxxx
Andrew
I do believe you were able to find the correct answer by yourself.
It is not the sum of both expectations equal to 1$?
If so E(loose)= 1$ - 0.5898$ = 0,4102$
Isn´t it?
_____licas (Luis A. Afonso)
.
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- probability question
- From: Andrew Schuyler
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- From: \"Luis A. Afonso\"
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