Jack , *the stripper*



*** Even if you accept the binomial expansion as being correct, the j=0 term is 1, not (1-p)^k.

Jack ***


Had you notice that YOU ARE COMPLETELY WRONG?

___(a + b)^k = kC0 * a ^ k * b^0 + …
___________= a ^ k +...

___a = 1 - p , b = p

Not 1, NEVER EVER!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

(when you attend High School did you failed the lesson to go to skate? - You slipped majestically, nose to the ground).

(cft. what I wrote on Jun. 28, 2006 5:27 AM).

BE MORE CAREFUL.


_______licas (Luis A. Afonso)
.



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