Re: Anybody know how to calculate this condiditonal Probability ?
- From: Xufei.Wang@xxxxxxxxx
- Date: 18 Aug 2006 15:04:31 -0700
So helpful explanations, thank you very much.
Yes, I should find out the mechanism, that means there is no general
way to calculate the final dose without caring the conbination of the
seperated factors.
For different system, they may have different models and thus need
different calculations. Is it right ?
illywhacker wrote:
Xufei.Wang@xxxxxxxxx wrote:
Dears
If P (Qt | Q, fi), (i=1,2,....,n), have been separately calculated,
How to calculate the probability distribution of P (Qt | Q, f1,
f2...fn)?
Is it just simply the sum of P (Qt | Q, fi)?
Or in more complicated way?
Is it depends on the relationship of the factors fi, f2... fn?
More information is needed for the calculation?
Yes, you need more information in general. Look at the case with just
two
f's, call them f and g. Then
P(Qt | f, g, Q) = P(Qt, f, g | Q) / P(f, g | Q) .
Now we can perhaps assume that f and g are independent of Q and of each
other:
P(Qt | f, g, Q) = P(Qt, f, g | Q) / (P(f) P(g)) .
Now,
P(Qt, f, g | Q) = P(g | Qt, f, Q) P(Qt, f | Q)
= P(g | Qt, f, Q) P(Qt | f, Q) P(f) .
Now *if*
P(g | Qt, f, Q) = P(g | Qt, Q) = P(Qt | g, Q) P(g) / P(Qt | Q) , (1)
where
P(Qt | Q) = \int dg P(Qt | g, Q) P(g) ,
then
P(Qt | f, g, Q) = P(Qt | f, Q) P(Qt | g, Q) / P(Qt | Q) .
The assumption, equation (1), that we know nothing about g if we know
Q,
Qt, and f, is almost certainly false. Indeed almost the opposite is
true:
if we know Q, Qt, and f, we may know g exactly. This is why, as I said
in
my previous post, you need to analyse the physics of the situation, to
know
how f and g together affect the irradiation. Knowing how they do it
separately is not enough. Now maybe they do not affect one another in
some
sense, but maybe they do. Probability cannot tell you this.
illywhacker;
.
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