Re: Dice problem - follow up

From: Schizoid Man <schiz@xxxxxx>
Date: Tue, 19 Sep 2006 00:30:19 +0100

Graeme wrote:

Since I'm calculating for AT LEAST one correct guess can I add the
probabilities
of success for 1,2,3 and 4 correct guesses together.
= 0.517746914

Graeme,

I think you might be thinking of too sophisticated a solution here.

Prob (at least one correct guess) = 1 - Prob (zero correct guesses)

Zero correct guesses (out of four chances) = (5/6) ^ 4

So prob (at least one correct guess) = 51.x%
.

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